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Which of the following statement is corr...

Which of the following statement is correct ?

A

`Fe^(3)` give a deep green ppt. on adding `K_(4)[Fe(CN)_(6)]` solution

B

On boiling a solution having `K^(+), Ca^(2+)` and `HCO_(3)^(-)` ions, we get a precipitate of `K_(2) [Co(CO_(3))_(2)]`

C

Manganese salts gives a violet borax bead test in reducing flame

D

From a mixed precipitate of AgCl and Agl, ammonia solution dissolves only AgCl

Text Solution

AI Generated Solution

The correct Answer is:
To determine which statement is correct, let's analyze each statement provided in the question step by step. ### Step 1: Analyze the Statements 1. **Statement 1**: "Fe³⁺ gives a deep blue precipitate on addition of K₄[Fe(CN)₆] solution." - This statement is incorrect. The addition of K₄[Fe(CN)₆] to Fe³⁺ ions produces a blue precipitate known as Prussian Blue, but it is not a deep blue precipitate. 2. **Statement 2**: "On boiling a solution having K⁺, Ca²⁺, and bicarbonate ion, we will get a precipitate of K₂CO₃." - This statement is also incorrect. When bicarbonate ions are boiled, they decompose to form carbon dioxide and water, and K₂CO₃ does not precipitate out. 3. **Statement 3**: "Manganese salts give a violet borax bead test in a reducing flame." - This statement is incorrect. Manganese salts give a gray borax bead test in a reducing flame, not violet. 4. **Statement 4**: "From a mixed precipitate of AgCl and AgI, ammonia solution dissolves only AgCl." - This statement is correct. Ammonia can dissolve AgCl to form a complex ion (Ag(NH₃)₂⁺), while AgI remains insoluble. ### Conclusion The correct statement is **Statement 4**: "From a mixed precipitate of AgCl and AgI, ammonia solution dissolves only AgCl." ---

To determine which statement is correct, let's analyze each statement provided in the question step by step. ### Step 1: Analyze the Statements 1. **Statement 1**: "Fe³⁺ gives a deep blue precipitate on addition of K₄[Fe(CN)₆] solution." - This statement is incorrect. The addition of K₄[Fe(CN)₆] to Fe³⁺ ions produces a blue precipitate known as Prussian Blue, but it is not a deep blue precipitate. 2. **Statement 2**: "On boiling a solution having K⁺, Ca²⁺, and bicarbonate ion, we will get a precipitate of K₂CO₃." - This statement is also incorrect. When bicarbonate ions are boiled, they decompose to form carbon dioxide and water, and K₂CO₃ does not precipitate out. ...
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