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A soldium salt of unknown anion when tre...

A soldium salt of unknown anion when treated with `MgCl_(2)` gives white precipitate only on boiling. The anion is:

A

`SO_(4)^(2-)`

B

`HCO_(3)^(-)`

C

`CO_(3)^(2-)`

D

`NO_(3)^(-)`

Text Solution

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The correct Answer is:
To solve the question regarding the unknown anion in the sodium salt that reacts with MgCl₂ to form a white precipitate upon boiling, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Reaction**: We know that when the sodium salt of an unknown anion is treated with MgCl₂, a reaction occurs that produces a white precipitate upon boiling. 2. **Consider Possible Anions**: The most likely candidates for anions that could form a precipitate with magnesium ions (Mg²⁺) include carbonate (CO₃²⁻), bicarbonate (HCO₃⁻), and others. However, we need to focus on the behavior of these anions when heated. 3. **Analyze Bicarbonate Ion**: The bicarbonate ion (HCO₃⁻) is known to react with magnesium ions. When MgCl₂ is added to a solution containing bicarbonate ions, it forms a soluble complex initially. The reaction can be represented as: \[ Mg^{2+} + 2 HCO_3^- \rightarrow Mg(HCO_3)_2 \text{ (soluble complex)} \] 4. **Effect of Boiling**: Upon boiling, the soluble complex decomposes, leading to the formation of magnesium carbonate (MgCO₃), which is insoluble in water and thus precipitates out as a white solid: \[ Mg(HCO_3)_2 \rightarrow MgCO_3 \downarrow + H_2O + CO_2 \uparrow \] 5. **Conclusion**: Since the white precipitate forms only upon boiling, this indicates that the anion involved is indeed bicarbonate (HCO₃⁻). Therefore, the unknown anion in the sodium salt is **bicarbonate ion (HCO₃⁻)**. ### Final Answer: The anion is **bicarbonate ion (HCO₃⁻)**.
To solve the question regarding the unknown anion in the sodium salt that reacts with MgCl₂ to form a white precipitate upon boiling, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Reaction**: We know that when the sodium salt of an unknown anion is treated with MgCl₂, a reaction occurs that produces a white precipitate upon boiling. 2. **Consider Possible Anions**: The most likely candidates for anions that could form a precipitate with magnesium ions (Mg²⁺) include carbonate (CO₃²⁻), bicarbonate (HCO₃⁻), and others. However, we need to focus on the behavior of these anions when heated. ...
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