Home
Class 11
CHEMISTRY
A solution of a metal ion when treated w...

A solution of a metal ion when treated with KI solution gives a red precipitate which dissolves in excess of KI solution to give a colourless solution. Moreover, the solution of the same metal ion on treatment with the solution of cobalt (II) thiocyanate gives rise to a deep blue crystalline precipitate. The metal ion is

A

`Pb^(2+)`

B

`Hg^(2+)`

C

`Cu^(2+)`

D

`Co^(2+)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to identify the metal ion based on the reactions described. Here’s a step-by-step breakdown of the solution: ### Step 1: Analyze the Reaction with KI When a metal ion solution is treated with KI (potassium iodide), it forms a red precipitate. This indicates the formation of a compound that contains iodine. The red precipitate is likely to be **HgI2 (mercury(II) iodide)**. **Hint:** Look for metal ions that form colored precipitates with iodide ions. ### Step 2: Formation of Colorless Solution The problem states that the red precipitate dissolves in excess KI to give a colorless solution. This is characteristic of the formation of **K2HgI4 (potassium tetraiodomercurate(II))**, which is soluble in excess iodide. **Hint:** Excess of KI can lead to the formation of soluble complexes. ### Step 3: Reaction with Cobalt(II) Thiocyanate Next, the same metal ion solution reacts with cobalt(II) thiocyanate to produce a deep blue crystalline precipitate. This indicates the formation of a complex with cobalt and the metal ion. The deep blue precipitate is likely to be **Hg(SCN)2 (mercury(II) thiocyanate)**. **Hint:** The formation of colored complexes often indicates the presence of specific metal ions. ### Step 4: Conclusion Based on the reactions described: - The red precipitate formed with KI is **HgI2**. - The colorless solution formed in excess KI is **K2HgI4**. - The deep blue precipitate formed with cobalt(II) thiocyanate is **Hg(SCN)2**. Thus, the metal ion in question is **Hg²⁺ (mercury(II) ion)**. **Final Answer:** The metal ion is **Hg²⁺ (mercury(II) ion)**.
To solve the problem, we need to identify the metal ion based on the reactions described. Here’s a step-by-step breakdown of the solution: ### Step 1: Analyze the Reaction with KI When a metal ion solution is treated with KI (potassium iodide), it forms a red precipitate. This indicates the formation of a compound that contains iodine. The red precipitate is likely to be **HgI2 (mercury(II) iodide)**. **Hint:** Look for metal ions that form colored precipitates with iodide ions. ### Step 2: Formation of Colorless Solution ...
Promotional Banner

Similar Questions

Explore conceptually related problems

A solution of a metal ion when treated with KI gives a red precipitate which dissolves in excess KI to give a colourless solution. Moreover, the solution of metal ion on treatment with a solution of cobalt (II) thiocyanate gives rise to a deep blue crystalline precipitate. The metal ion is

A solution of a metal ion when treated with KI gives a red precipitate which dissolves in excess KI to give a colourless solution.Moreover, the solution of metal ion on treatment with a solution of cobalt (II) thiocyanate gives rise to a deep blue crystalline precipitate.The metal ion is:

A solutionf of a metal ion when treated with KI gives a red precipitate which dissolves in excess KI to give a colourless solution.Moreover, the solution of metal ion on treatment with a solution of cobalt (II) thiocyanate gives rise to a deep-blue crystalline precipitate. The metal ions is

A metal nitrate reacts with KI solution to give a block precipitate which on addition of excess of KI solution forms an orange coloured solution. The cation of metal nitrate is :

A metal nitrate reacts with KI to give a black precipitate which on addition of excess of Kl is converted into orange colour solution.The cation of the metal nitrate is :

A solution of Hg^(2+) ion on treatment with a solution of cobalt (II) thiocyanate gives rise to a deep blue crystalline precipitate .Then the coordination number of mercury in the deep blue coloured compound is:

Which of the following ions gives coloured solution?

When a KI solution is added to a metal nitrate, a black precipitate is produced which dissolves in an excess of KI to give an organge solution. The metal ion is:

A metal nitrate reacts with Kl solution to give yellow precipitate which on addition of excess of more concentrated solution (6 M) of Kl dissolves forming a solution.The cation of metal nitrate is: