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When KI is added to acidified solution o...

When KI is added to acidified solution of solution of sodium nitrite :

A

`NO` gas is liberated and `I_(2)` is set free

B

`N_(2)` gas is liberated and HI is produced

C

`N_(2)O` gas is liberated and `I_(2)` is set free

D

`N_(2)` gas is liberated and HOI is produced

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The correct Answer is:
To solve the question of what happens when KI is added to an acidified solution of sodium nitrite (NaNO2), we can break down the reaction step by step. ### Step-by-Step Solution: 1. **Identify the Reactants**: - We have potassium iodide (KI) and sodium nitrite (NaNO2) in an acidified solution. The acid can be represented as H+ (from a strong acid like sulfuric acid). 2. **Write the Chemical Equation**: - When KI is added to the acidified solution of sodium nitrite, the iodide ions (I-) from KI can react with the nitrite ions (NO2-) from sodium nitrite in the presence of H+ ions. 3. **Determine the Products**: - The reaction leads to the formation of nitrogen monoxide (NO), iodine (I2), and water (H2O). The balanced chemical equation for this reaction is: \[ 2KI + NaNO2 + 2H^+ \rightarrow 2I_2 + NO + H_2O \] - However, we can simplify it to focus on the main products: \[ 2KI + 2H^+ + NaNO2 \rightarrow NO + I_2 + H_2O \] 4. **Identify the Observations**: - The formation of nitrogen monoxide (NO) gas and iodine (I2) indicates that both gases are liberated during the reaction. - Iodine may impart a brown color to the solution, while NO is a colorless gas. 5. **Conclusion**: - The correct statement regarding the reaction is that NO gas is liberated and I2 is set free. ### Final Answer: When KI is added to an acidified solution of sodium nitrite, nitrogen monoxide (NO) gas is liberated, and iodine (I2) is set free. ---

To solve the question of what happens when KI is added to an acidified solution of sodium nitrite (NaNO2), we can break down the reaction step by step. ### Step-by-Step Solution: 1. **Identify the Reactants**: - We have potassium iodide (KI) and sodium nitrite (NaNO2) in an acidified solution. The acid can be represented as H+ (from a strong acid like sulfuric acid). 2. **Write the Chemical Equation**: ...
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