Match the list I with list II and select the correct answer using the code given below the lists.
`{:(,"List I",,"List II",),(P,Sr^(2+),1,"Golden yellow",),(Q,K^(+),2,"Apple green",),(R,Na^(+),3,"Crimson red",),(S,Ba^(2+),4,"Lilac",):}`

Options

A. `{:(P,Q,R,S,),(1,2,3,4,):}`
B. `{:(P,Q,R,S,),(3,4,1,2,):}`
C. `{:(P,Q,R,S,),(2,1,4,3,):}`
D. `{:(P,Q,R,S,),(4,3,1,2,):}`

Explanation

To solve the problem of matching List I with List II, we will go through each ion in List I and identify the corresponding color from List II based on known flame test colors.

### Step-by-Step Solution:

1. **Identify the ions in List I:**
- P: Sr²⁺ (Strontium ion)
- Q: K⁺ (Potassium ion)
- R: Na⁺ (Sodium ion)
- S: Ba²⁺ (Barium ion)

2. **Identify the colors associated with each ion from List II:**
- 1: Golden yellow
- 2: Apple green
- 3: Crimson red
- 4: Lilac

3. **Match each ion with its corresponding color:**
- **For P (Sr²⁺):** Strontium ions produce a crimson red flame. Therefore, P matches with 3 (Crimson red).
- **For Q (K⁺):** Potassium ions produce a lilac flame. Therefore, Q matches with 4 (Lilac).
- **For R (Na⁺):** Sodium ions produce a golden yellow flame. Therefore, R matches with 1 (Golden yellow).
- **For S (Ba²⁺):** Barium ions produce an apple green flame. Therefore, S matches with 2 (Apple green).

4. **Summarize the matches:**
- P → 3 (Crimson red)
- Q → 4 (Lilac)
- R → 1 (Golden yellow)
- S → 2 (Apple green)

5. **Write the final answer using the code:**
- The correct matches are:
- P = 3
- Q = 4
- R = 1
- S = 2

### Final Answer Code:
- The answer code is: **P-3, Q-4, R-1, S-2**

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