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A yellow turbidity, sometimes appears on...

A yellow turbidity, sometimes appears on passing `H_(2)S` gas ever in the absence of the second group radicals. This happens because

A

sulphur is present in the mixture as an impurity

B

the fourth group radicals are precipitated as sulphides

C

`H_(2)S` is oxidised by some acidic radical present in solution

D

the third group radicals are precipitated
Aqueous sodium hydroxide reacts with a metal ion

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The correct Answer is:
To solve the question regarding the appearance of yellow turbidity when passing H₂S gas in the absence of second group radicals, we can follow these steps: ### Step 1: Understand the nature of H₂S gas H₂S (hydrogen sulfide) is a colorless gas with a characteristic odor of rotten eggs. It is known to react with various substances, particularly in acidic conditions. **Hint:** Recall the properties of H₂S and its behavior in chemical reactions. ### Step 2: Identify the conditions of the reaction The question specifies that the yellow turbidity appears in the absence of second group radicals. Second group radicals typically refer to metal ions that can precipitate as sulfides when reacting with H₂S. **Hint:** Consider what happens to H₂S when no second group radicals are present. ### Step 3: Consider the oxidation of H₂S In certain conditions, H₂S can be oxidized. This oxidation can occur in the presence of acidic radicals or other oxidizing agents. The oxidation of H₂S can lead to the formation of sulfur or other sulfur compounds. **Hint:** Think about what products can form when H₂S is oxidized. ### Step 4: Formation of yellow precipitate When H₂S is oxidized, it can lead to the formation of elemental sulfur, which is yellow in color. This is the yellow turbidity observed in the solution. The presence of acidic conditions can facilitate this oxidation process. **Hint:** Recall the color and properties of sulfur and how it can appear in a solution. ### Step 5: Conclusion Thus, the yellow turbidity observed when passing H₂S gas, even in the absence of second group radicals, is due to the oxidation of H₂S to form elemental sulfur. **Hint:** Summarize the process: H₂S → Oxidation → Yellow sulfur precipitate. ### Final Answer The yellow turbidity appears because H₂S is oxidized to form elemental sulfur, resulting in a yellow precipitate.
To solve the question regarding the appearance of yellow turbidity when passing H₂S gas in the absence of second group radicals, we can follow these steps: ### Step 1: Understand the nature of H₂S gas H₂S (hydrogen sulfide) is a colorless gas with a characteristic odor of rotten eggs. It is known to react with various substances, particularly in acidic conditions. **Hint:** Recall the properties of H₂S and its behavior in chemical reactions. ### Step 2: Identify the conditions of the reaction ...
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