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An aqueous solution of a mixture of two ...

An aqueous solution of a mixture of two inorganic salts when treated with dilute HCl, gave a precipitate (P) and a filtrate (Q). The precipitate (P) was found to dissolve in hot water. The filtrate (Q) remained unchanged, when treated with `H_(2)S` in a dilute mineral acid medium. However, it gave a green precipitate (R) `H_(2)S` in an ammoniacal medium. The precipitate (R) gave a coloured solution (S), when treated with `H_(2)O_(2)` in an aqueous NaOH medium.
The precipitate P contains

A

`Pb^(2+)`

B

`Hg_(2)^(2+)`

C

`Ag^(+)`

D

`Hg^(2+)`

Text Solution

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The correct Answer is:
To solve the question regarding the precipitate (P) formed when an aqueous solution of a mixture of two inorganic salts is treated with dilute HCl, we will follow the clues provided in the problem step-by-step. ### Step 1: Identify the reaction with dilute HCl When the mixture of two inorganic salts is treated with dilute HCl, it produces a precipitate (P) and a filtrate (Q). **Hint:** Consider common inorganic salts that react with dilute HCl to form precipitates. ### Step 2: Analyze the properties of precipitate (P) The problem states that precipitate (P) dissolves in hot water. This indicates that precipitate (P) is likely a salt that is soluble in hot water. **Hint:** Think about which metal salts are known to be soluble in hot water. ### Step 3: Analyze the filtrate (Q) The filtrate (Q) remains unchanged when treated with H2S in a dilute mineral acid medium. This suggests that the ions present in Q do not form any precipitate with H2S under these conditions. **Hint:** Consider the solubility rules for sulfides and which ions do not precipitate with H2S. ### Step 4: Reacting filtrate (Q) with H2S in ammoniacal medium When Q is treated with H2S in an ammoniacal medium, it produces a green precipitate (R). This indicates that Q contains chromium ions, as chromium(III) sulfide (Cr2S3) can form a green precipitate under these conditions. **Hint:** Recall the behavior of chromium ions in different media. ### Step 5: Analyze the reaction of precipitate (R) The green precipitate (R) gives a colored solution (S) when treated with H2O2 in an aqueous NaOH medium. The reaction of chromium(III) compounds with hydrogen peroxide in a basic medium typically leads to the formation of chromate ions (CrO4^2-), which are yellow. **Hint:** Think about the oxidation states of chromium and how they change in reactions with oxidizing agents. ### Conclusion Based on the analysis: - The precipitate (P) formed from the reaction with dilute HCl is likely lead(II) chloride (PbCl2), which is soluble in hot water. - The filtrate (Q) contains chromium ions (Cr^3+), which do not precipitate with H2S in acidic conditions but do form a precipitate in ammoniacal conditions. Thus, the precipitate P contains **lead (Pb)**. ### Final Answer The precipitate P contains **lead (Pb)**.
To solve the question regarding the precipitate (P) formed when an aqueous solution of a mixture of two inorganic salts is treated with dilute HCl, we will follow the clues provided in the problem step-by-step. ### Step 1: Identify the reaction with dilute HCl When the mixture of two inorganic salts is treated with dilute HCl, it produces a precipitate (P) and a filtrate (Q). **Hint:** Consider common inorganic salts that react with dilute HCl to form precipitates. ### Step 2: Analyze the properties of precipitate (P) ...
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