Draw the structures of the following compounds
(i) Hex-2-enoic acid
(ii) 2-chloro-2-methylbutan-1-ol
(iii) 5,5-Diethylnonan-3-ol
(iv) Propane-1,3-diamine
(v) 4-Nitropent-1-yne
(vi) But-2-ene-1,4-dioic acid
(vii) 4-Amino-2-ethylpent-2-enal
(viii) Ethyl-3-methoxy-4-nitrobutanoate
(ix) 5-ethyl-3-methyloctane
(x) Hex-4-yn-2-one

Explanation

To draw the structures of the given organic compounds, we will follow a systematic approach for each compound based on its IUPAC name. Here’s the step-by-step solution:

### (i) Hex-2-enoic acid
1. **Identify the carbon chain**: "Hex" indicates 6 carbon atoms.
2. **Position of the double bond**: "2-enoic" indicates a double bond at the second carbon.
3. **Carboxylic acid group**: "oic acid" indicates the presence of a carboxylic acid group (-COOH) at the first carbon.
4. **Draw the structure**:
- Start with a 6-carbon chain.
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