The IUPAC name for `CH_(3)CH_(2)CH_(2)CH(CH=CH_(2))CH_(2)CH_(2)CH_(3)` is

Options

A. 4-Ethenylheptane
B. 3-n-propylhex-1-ene
C. 3-Ethenylheptane
D. None of these

Explanation

To determine the IUPAC name for the compound `CH₃CH₂CH₂CH(CH=CH₂)CH₂CH₂CH₃`, we will follow these steps:

### Step 1: Draw the Structure
First, we can visualize the structure of the compound. The compound can be represented as:
```
CH3
|
CH2-CH2-CH-CH=CH2
|
CH2-CH2-CH3
```
This shows a straight chain of carbon atoms with a double bond on one of the branches.

### Step 2: Identify the Longest Carbon Chain
Next, we need to identify the longest continuous carbon chain. In this case, we can see that the longest chain consists of 6 carbon atoms.

### Step 3: Number the Carbon Chain
We will number the carbon chain starting from the end closest to the double bond to give the double bond the lowest possible number.
- The numbering will be as follows:
```
1 2 3 4 5 6
CH3-CH2-CH-CH2-CH2-CH3
|
CH=CH2
```
This gives us a double bond starting at carbon 4.

### Step 4: Identify the Substituents
Now, we need to identify any substituents on the main chain. We have a propyl group (3 carbon atoms) branching off from carbon 3.

### Step 5: Write the Name
Now we can write the IUPAC name:
- The longest chain is hexane (6 carbons).
- The double bond is located at carbon 4, so we use "hex-4-ene".
- The substituent is a propyl group at carbon 3, so we add "3-propyl".

Putting it all together, the IUPAC name is:
**3-propyl-hex-4-ene**

### Final Answer
The IUPAC name for the compound `CH₃CH₂CH₂CH(CH=CH₂)CH₂CH₂CH₃` is **3-propyl-hex-4-ene**.

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