The IUPAC name of
`CH_(2)=CH-CH(CH_(3)CH_(2))overset(overset(Br)(|))(C)=CH_(2)` is :

Options

A. 4 Bromo-3-ethyl-1, 4-pentadiene
B. 2-Bromo-3-ethyl-1,4-pentadiene
C. 2-Bromo-3-ethyl-1,5-pentadiene
D. None of these

Explanation

To determine the IUPAC name of the compound `CH2=CH-CH(CH3CH2)Br=CH2`, we will follow these steps:

### Step 1: Identify the Structure
First, we need to visualize the structure of the compound. The given structure can be expanded to show the connections clearly. The compound has a double bond and a bromine substituent.

### Step 2: Find the Longest Carbon Chain
Next, we need to identify the longest continuous carbon chain in the structure. In this case, the longest chain consists of 5 carbon atoms.

### Step 3: Number the Carbon Chain
We will number the carbon chain starting from the end closest to the first double bond. The numbering will be as follows:
1. C1: CH2 (double bond)
2. C2: CH (double bond)
3. C3: CH (with an ethyl group)
4. C4: CH (bromine attached)
5. C5: CH2 (double bond)

### Step 4: Identify Substituents
From the numbering:
- At position 2, there is a bromine (Br) substituent.
- At position 3, there is an ethyl (C2H5) group.

### Step 5: Identify the Type of Hydrocarbon
The compound contains two double bonds, which means it is a diene. Since there are 5 carbons in the longest chain, it is a pentadiene.

### Step 6: Combine the Information
Now, we can combine the information:
- The double bonds are located at positions 1 and 4, so we denote this as 1,4-pentadiene.
- The substituents are bromine at position 2 and ethyl at position 3.

### Step 7: Write the Full IUPAC Name
Putting it all together, the IUPAC name of the compound is:
**2-bromo-3-ethyl-1,4-pentadiene**

### Final Answer
The IUPAC name of the compound `CH2=CH-CH(CH3CH2)Br=CH2` is **2-bromo-3-ethyl-1,4-pentadiene**.

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