The correct IUPAC name of the compound
`{:(H_(3)C-C=CH-CH-CH_(3)),(" | |"),(" "Cl" "CH_(3)):}`

Options

A. 2-Chloro-4-methypent-2-ene
B. 4-Chloro-2-methylpent-3-ene
C. 4-Methyl-2-chloropent-2-ene
D. 2-Chloro-4-,dimethylbut-2-ene

Explanation

To determine the correct IUPAC name of the given compound, we will follow a systematic approach:

### Step 1: Identify the Structure
The compound is represented as:
```
CH3
|
H3C-C=CH-CH-CH3
| |
Cl CH3
```
From this structure, we can see that there is a carbon chain with a double bond and two substituents (Cl and CH3).

### Step 2: Determine the Longest Carbon Chain
We need to find the longest continuous carbon chain that includes the double bond. In this case, the longest chain consists of 5 carbon atoms.

### Step 3: Number the Carbon Chain
To give the double bond the lowest possible number, we will number the carbon chain from the end nearest to the double bond:
1. C1: CH3
2. C2: C (double bond)
3. C3: CH
4. C4: CH
5. C5: CH3

### Step 4: Identify the Position of the Double Bond
The double bond is between C2 and C3. Thus, we will indicate this in the name as "2-ene".

### Step 5: Identify and Name the Substituents
We have two substituents:
- A chlorine (Cl) on C2
- A methyl (CH3) group on C4

### Step 6: Assign Locants to the Substituents
When naming the substituents, we will use the alphabetical order:
- "Chloro" comes before "methyl" in alphabetical order.

### Step 7: Construct the IUPAC Name
Putting all the information together, we have:
- The base name for the 5-carbon alkene is "pent".
- The double bond is at position 2, so we write "pent-2-ene".
- The substituents are "2-chloro" and "4-methyl".

Thus, the complete IUPAC name is:
**2-chloro-4-methylpent-2-ene**

### Step 8: Verify with Options
We will check the options provided to see if our answer matches. The correct option is:
**Option A: 2-chloro-4-methylpent-2-ene**

### Final Answer
The correct IUPAC name of the compound is:
**2-chloro-4-methylpent-2-ene**

---