Describe the change in hybridisation (if any) of the `AI` atom in the following:
`AlCl_(3)+Cl^(ө)rarr AlCl_(4)^(ө)`

Explanation

To determine the change in hybridization of the aluminum (Al) atom in the reaction \( \text{AlCl}_3 + \text{Cl}^- \rightarrow \text{AlCl}_4^- \), we can follow these steps:

### Step 1: Analyze the initial state of Al in AlCl3
- Aluminum (Al) has three valence electrons and is in group 13 of the periodic table.
- In \( \text{AlCl}_3 \), aluminum forms three bonds with three chlorine atoms.

**Hybridization in AlCl3:**
- The aluminum atom uses one s orbital and two p orbitals to form three sigma bonds with chlorine.
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