Give the change in bond order in the following ionisation process?
i. `O_(2) rarr O_(2)^(o+)+e^(-)` , ii.`N_(2) rarr N_(2)^(o+)+e^(-)`

Explanation

To determine the change in bond order for the given ionization processes, we will follow these steps:

### Step 1: Determine the bond order of O₂
O₂ has a total of 16 electrons (8 from each oxygen atom). The bond order can be calculated using the formula:
\[ \text{Bond Order} = \frac{(\text{Number of bonding electrons} - \text{Number of antibonding electrons})}{2} \]

For O₂, the molecular orbital configuration is:
\[ \sigma_{1s}^2 \sigma_{1s}^*^2 \sigma_{2s}^2 \sigma_{2s}^*^2 \sigma_{2p_z}^2 \pi_{2p_x}^2 \pi_{2p_y}^2 \pi_{2p_x}^*^1 \pi_{2p_y}^*^0 \]
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