Describe hybridisation in the case of `PCl_(5) and SF_(6)` The axial bonds are longer as compared to equatorial bonds in `PCl_(5)` whereas in `SF_(6)` both axial bonds and equatorial bonds and have the same bond length. Explain.

Explanation

`PCl_(5) : H=1//2[5+5-0+0]=5(sp^(3)d)`
`SF_(6) : H=1//2[6+6-0+0]=6(sp^(3)d^(2))`
For the shapes of these molecules and bonding parameters, consult section 4.14.