Write two resonance structure of `N_2 O` that satisfy the octet rule.

Explanation

To write two resonance structures of \( N_2O \) (dinitrogen monoxide) that satisfy the octet rule, we will follow these steps:

### Step 1: Count the total number of valence electrons
- Nitrogen (N) has 5 valence electrons, and Oxygen (O) has 6 valence electrons.
- For \( N_2O \), we have:
\[ 2 \times 5 + 6 = 16 \text{ valence electrons} \]
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