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Which out of the following pairs has dip...

Which out of the following pairs has dipole moment ?
(i) `BF_(3) and NCl_(3)` (ii) `H_(2)Oand BF_(3)` (iii) `CO_(2) and H_(2)S`

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The correct Answer is:
To determine which pairs have a dipole moment, we need to analyze the molecular geometry and electronegativity of the atoms involved in each pair. A dipole moment occurs when there is an uneven distribution of electron density, leading to a separation of charge. ### Step-by-Step Solution: 1. **Analyzing BF3 and NCl3:** - **BF3 (Boron Trifluoride):** - Geometry: Trigonal planar. - Boron has three valence electrons and forms three bonds with fluorine. - The dipoles from each B-F bond point towards the more electronegative fluorine atoms. - Since the molecule is symmetric, the dipoles cancel each other out. - **Result:** Dipole moment (μ) = 0. - **NCl3 (Nitrogen Trichloride):** - Geometry: Trigonal pyramidal (due to one lone pair on nitrogen). - Nitrogen has five valence electrons and forms three bonds with chlorine. - The dipoles from each N-Cl bond point towards the more electronegative chlorine atoms. - The lone pair on nitrogen creates an asymmetry, so the dipoles do not cancel out completely. - **Result:** Dipole moment (μ) ≠ 0. **Conclusion for (i):** NCl3 has a dipole moment, while BF3 does not. 2. **Analyzing H2O and BF3:** - **H2O (Water):** - Geometry: Bent (due to two lone pairs on oxygen). - Oxygen is more electronegative than hydrogen, creating a dipole towards oxygen. - The bent shape means the dipoles do not cancel out. - **Result:** Dipole moment (μ) ≠ 0. - **BF3:** (already analyzed) - **Result:** Dipole moment (μ) = 0. **Conclusion for (ii):** H2O has a dipole moment, while BF3 does not. 3. **Analyzing CO2 and H2S:** - **CO2 (Carbon Dioxide):** - Geometry: Linear. - Carbon forms double bonds with two oxygen atoms. - The dipoles from each C=O bond point towards the oxygen atoms. - The linear shape means the dipoles are equal in magnitude but opposite in direction, cancelling each other out. - **Result:** Dipole moment (μ) = 0. - **H2S (Hydrogen Sulfide):** - Geometry: Bent (similar to H2O). - Sulfur is less electronegative than oxygen but still creates a dipole towards sulfur. - The bent shape means the dipoles do not cancel out completely. - **Result:** Dipole moment (μ) ≠ 0. **Conclusion for (iii):** H2S has a dipole moment, while CO2 does not. ### Final Summary: - **Pairs with dipole moments:** - (i) NCl3 - (ii) H2O - (iii) H2S
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