Home
Class 11
CHEMISTRY
Which of the following molecules behave ...

Which of the following molecules behave as electrical dipoles ?
(i) `C Cl_(4)` (ii) `CHCl_(3)` (iii) `BF_(3)` (iv) `H_(2)O` (v) `BeF_(2)` (vi) `NH_(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given molecules behave as electrical dipoles, we need to analyze the molecular geometry and polarity of each molecule. An electrical dipole occurs when there is a separation of positive and negative charges within a molecule, leading to a net dipole moment. ### Step-by-step Solution: 1. **Analyze CCl₄ (Carbon Tetrachloride)**: - Structure: Tetrahedral geometry with four Cl atoms bonded to C. - Polarity: Each C-Cl bond is polar due to the electronegativity difference between C and Cl. However, the symmetrical arrangement causes the dipoles to cancel each other out. - **Conclusion**: CCl₄ does not behave as an electrical dipole (Dipole moment = 0). 2. **Analyze CHCl₃ (Chloroform)**: - Structure: Tetrahedral geometry with one H atom and three Cl atoms bonded to C. - Polarity: The C-H bond is less polar than the C-Cl bonds. The dipoles from the three C-Cl bonds do not completely cancel due to the presence of the hydrogen atom. - **Conclusion**: CHCl₃ behaves as an electrical dipole (Dipole moment ≠ 0). 3. **Analyze BF₃ (Boron Trifluoride)**: - Structure: Trigonal planar geometry with three F atoms bonded to B. - Polarity: Each B-F bond is polar, but the symmetrical arrangement leads to cancellation of dipole moments. - **Conclusion**: BF₃ does not behave as an electrical dipole (Dipole moment = 0). 4. **Analyze H₂O (Water)**: - Structure: Bent geometry with two H atoms and two lone pairs on O. - Polarity: The O-H bonds are polar, and the bent shape prevents cancellation of dipole moments. - **Conclusion**: H₂O behaves as an electrical dipole (Dipole moment ≠ 0). 5. **Analyze BeF₂ (Beryllium Fluoride)**: - Structure: Linear geometry with two F atoms bonded to Be. - Polarity: Each Be-F bond is polar, but the linear arrangement causes the dipoles to cancel out. - **Conclusion**: BeF₂ does not behave as an electrical dipole (Dipole moment = 0). 6. **Analyze NH₃ (Ammonia)**: - Structure: Trigonal pyramidal geometry with one lone pair on N and three H atoms. - Polarity: The N-H bonds are polar, and the lone pair creates an asymmetrical shape, leading to a net dipole moment. - **Conclusion**: NH₃ behaves as an electrical dipole (Dipole moment ≠ 0). ### Final Answer: The molecules that behave as electrical dipoles are: - CHCl₃ - H₂O - NH₃
Promotional Banner

Similar Questions

Explore conceptually related problems

Which one of the following has the highest dipole moment? (i) CH_(2)Cl_(2) , (ii) CHCl_(3) , (iii) C Cl_(4)

Which of the following molecules are homoatomic ? (i) H_(2)O , (ii) O_(3) , (iii) NH_(3) , (iv) Cl_(2)

Which out of the following pairs has dipole moment ? (i) BF_(3) and NCl_(3) (ii) H_(2)Oand BF_(3) (iii) CO_(2) and H_(2)S

Which of the following molecules would you expect to be optically active ? (i) C Cl_2 (ii) CHCl Br F (iii) 2-methylbutane (iv) CH_3CH_2 COOH (v) Butan-2-ol (vi) 2-hydroxypropanoic acid.

Find the values of :- (i) 2^(4) (ii) 4^(3) (iii) 3^(2) (iv) 5^(3) (v) 9^(4) (vi) 7^(3)

Which of the following species are hypervalent ? (I) ClO_(4)^(-) " "(II) BF_(3) (III) SO_(4)^(-2)" "(IV) CO_(3)^(-2)

Which of the following molecules possess a triangular planar geometry? Be Cl_2 , BCl_3 , H_2 O , NH_3

How many of the following compound on hydrolysis form HCl? (i) NaCl (ii) PCl_(5) (iii) CH_(3)Cl (iv) NH_(4)Cl (v) BaCl_(2)

Give the conjugate bases of (i) H_(2)O (ii) HNO_(3) (iii) NH_(4)^(+) (Iv) HCO_(3)^(-).

Nucleophiles and electrophiles are reaction intermediates having electron rich and electron deficient centres respectively . Hence, they tend to attack electron deficient and electron rich centres respectively. Classify the following species as electrophiles and uncheophiles. (i) H_(3)CO^(-) (ii) H_(3)C-overset(O)overset(||)C-O^(-) (iii)Cl (iv) Cl_(2)C: (v) (H_(3)C)_(3)C^(+) (vi) Br^(-) (vii) H_(3)COH (viii) R-NH-R