Mention the state of hybridisation of all the carbon atoms in he molecule `CH_(2)=CH-CH=CH_(2)`

Answer

To determine the state of hybridization of all the carbon atoms in the molecule \( CH_2=CH-CH=CH_2 \), we can follow these steps:

### Step 1: Identify the Structure
The given molecule is buta-1,3-diene, which can be represented as:
```
H H
\ /
C
// \
C C
\ /
C
/ \
H H
```
Here, we have four carbon atoms (C1, C2, C3, C4) and their respective bonds.

### Step 2: Count the Bonds for Each Carbon Atom
- **C1**: Forms 3 bonds (2 with H and 1 with C2)
- **C2**: Forms 3 bonds (1 with C1, 1 with C3, and 1 double bond with C3)
- **C3**: Forms 3 bonds (1 with C2, 1 with C4, and 1 double bond with C4)
- **C4**: Forms 3 bonds (2 with H and 1 with C3)

### Step 3: Determine Hybridization
The hybridization can be determined based on the number of sigma bonds formed by each carbon atom:
- Each carbon atom forms 3 sigma bonds, which indicates that they are using one s orbital and two p orbitals to form hybrid orbitals.

Thus, the hybridization for each carbon atom can be concluded as follows:
- **C1**: sp² hybridized
- **C2**: sp² hybridized
- **C3**: sp² hybridized
- **C4**: sp² hybridized

### Final Answer
All the carbon atoms (C1, C2, C3, and C4) in the molecule \( CH_2=CH-CH=CH_2 \) are **sp² hybridized**.

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