In the molecular orbital configuration of `N_(2)` which orbital has lower energy : `sigma_(2pz)orpi_(2px)` ?

Answer

To determine which orbital has lower energy between `sigma_(2pz)` and `pi_(2px)` in the molecular orbital configuration of `N2`, we can follow these steps:

### Step 1: Write the Molecular Orbital Configuration of N2
The molecular orbital configuration for nitrogen (`N2`) is as follows:
- `σ(1s)²`
- `σ*(1s)²`
- `σ(2s)²`
- `σ*(2s)²`
- `π(2p_x)²`
- `π(2p_y)²`
- `σ(2p_z)²`

### Step 2: Identify the Energy Levels of the Orbitals
In molecular orbital theory, the energy levels of the orbitals increase as follows:
- `σ(1s) < σ*(1s) < σ(2s) < σ*(2s) < π(2p_x) = π(2p_y) < σ(2p_z)`

### Step 3: Compare the Energy of `sigma_(2pz)` and `pi_(2px)`
From the configuration and the energy level order:
- `π(2p_x)` and `π(2p_y)` are degenerate (have the same energy).
- `σ(2p_z)` has a higher energy than both `π(2p_x)` and `π(2p_y)`.

### Conclusion
Since `π(2p_x)` has lower energy than `σ(2p_z)`, we conclude that:
- **The orbital with lower energy is `π(2p_x)`**.