Draw Lewis structure of `N^(3-)` ion.

Answer

To draw the Lewis structure of the \( N^{3-} \) ion, follow these steps:

### Step 1: Determine the number of valence electrons
Nitrogen (N) has 5 valence electrons. Since we have a \( N^{3-} \) ion, it has gained 3 additional electrons.

**Calculation:**
- Valence electrons from nitrogen: 5
- Additional electrons due to the \( 3- \) charge: 3
- Total valence electrons = 5 + 3 = 8

### Step 2: Draw the Lewis structure
Now that we know there are 8 valence electrons to work with, we can draw the Lewis structure.

1. Start by placing the nitrogen atom in the center.
2. Distribute the 8 valence electrons around the nitrogen atom.
3. Each electron can be represented as a dot.
4. To represent the complete octet, we can pair the electrons.

**Drawing:**
- Place 5 electrons around the nitrogen atom to represent its original valence electrons.
- Add 3 more electrons to represent the additional electrons gained due to the \( 3- \) charge.

The final structure will look like this:

```
:N:
: : :
```
Where the colons represent pairs of electrons.

### Step 3: Confirm the octet rule
In this structure, nitrogen has 8 electrons around it, which satisfies the octet rule. Therefore, the structure is stable.

### Final Lewis Structure
The Lewis structure for the \( N^{3-} \) ion is represented as:

```
:N:
: : :
```
And we denote the charge as \( N^{3-} \) to indicate that it is an anion.

---