How many sigma bonds and pi bonds are present in a benzene molecules ? .

Answer

To determine the number of sigma and pi bonds in a benzene molecule, we can follow these steps:

### Step-by-Step Solution:

1. **Draw the Structure of Benzene**:
- Benzene (C6H6) has a hexagonal ring structure with alternating double bonds. Each carbon atom is bonded to one hydrogen atom.

2. **Identify the Types of Bonds**:
- In benzene, each carbon atom is bonded to two other carbon atoms and one hydrogen atom.
- The carbon-carbon bonds in benzene are alternating single and double bonds.

3. **Count the Sigma Bonds**:
- Each single bond is a sigma bond.
- Each double bond consists of one sigma bond and one pi bond.
- In benzene, there are 6 carbon-carbon bonds and 6 carbon-hydrogen bonds.
- The total number of sigma bonds can be calculated as follows:
- 6 C-C bonds (1 sigma each) = 6 sigma bonds
- 6 C-H bonds (1 sigma each) = 6 sigma bonds
- Total sigma bonds = 6 (C-C) + 6 (C-H) = **12 sigma bonds**.

4. **Count the Pi Bonds**:
- Each double bond contributes one pi bond.
- In benzene, there are 3 double bonds.
- Therefore, the total number of pi bonds = 3 (from the 3 double bonds) = **3 pi bonds**.

### Final Answer:
- **Total Sigma Bonds**: 12
- **Total Pi Bonds**: 3