The structure of `CH_(2)=C=CH_(2)` is :

Options

A. linear
B. planar
C. non-planar
D. has several resonating structures

Explanation

To determine the structure of the compound \( CH_2=C=CH_2 \), we can follow these steps:

### Step 1: Identify the Atoms and Bonds
The molecular formula \( CH_2=C=CH_2 \) indicates that there are three carbon atoms and four hydrogen atoms. The structure consists of two double bonds between the carbon atoms.

### Step 2: Draw the Basic Structure
Start by arranging the carbon atoms in a linear fashion since we have double bonds. The structure can be drawn as follows:
- The first carbon (C1) is bonded to two hydrogen atoms (H).
- The second carbon (C2) is bonded to the first carbon (C1) with a double bond and to the third carbon (C3) with another double bond.
- The third carbon (C3) is also bonded to two hydrogen atoms (H).

The basic structure looks like this:
```
H2C=C=CH2
```

### Step 3: Determine Hybridization
Next, we need to determine the hybridization of the central carbon atom (C2):
- C2 is bonded to two other carbon atoms through double bonds.
- Each carbon atom involved in a double bond has one \( sp \) hybrid orbital and one unhybridized p orbital.

Since C2 is involved in two double bonds, it has \( sp \) hybridization.

### Step 4: Identify the Geometry
The hybridization \( sp \) indicates that the geometry around the carbon atom is linear. Therefore, the angle between the bonds is approximately 180 degrees.

### Step 5: Final Structure
The final structure of \( CH_2=C=CH_2 \) is linear, with the hydrogen atoms positioned on either side of the carbon chain.

The complete structure can be represented as:
```
H2C=C=CH2
```
This confirms that the compound is linear due to the \( sp \) hybridization of the central carbon atom.

### Conclusion
The structure of \( CH_2=C=CH_2 \) is linear.

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