If a molecule `MX_(3)` has zero dipole moment, the state hybridisation of M is :

Options

A. `sp^(3)d`
B. sp.
C. `sp^(3)p^(2)`
D. `sp^(2)`

Explanation

To determine the hybridization of the central atom \( M \) in the molecule \( MX_3 \) that has a zero dipole moment, we can follow these steps:

### Step 1: Analyze the Molecular Geometry
The question states that the molecule \( MX_3 \) has a zero dipole moment. This indicates that the molecular geometry must be symmetrical. For a molecule with three identical substituents (like \( X \)) around a central atom (like \( M \)), the ideal geometry that allows for symmetry and cancellation of dipole moments is trigonal planar.

**Hint:** Remember that a symmetrical arrangement of bonds usually leads to a zero dipole moment.

### Step 2: Determine the Hybridization
In a trigonal planar geometry, the central atom \( M \) is surrounded by three bond pairs. The type of hybridization that corresponds to three regions of electron density (bond pairs) is \( sp^2 \).

**Hint:** The number of bond pairs around the central atom helps in identifying the hybridization type.

### Step 3: Conclusion
Thus, for the molecule \( MX_3 \) with a zero dipole moment, the hybridization of the central atom \( M \) is \( sp^2 \).

**Final Answer:** The hybridization of \( M \) in \( MX_3 \) is \( sp^2 \).