The pair of species having identical shapes for molecules of both species is ?

Options

A. `BF_(3),PCl_(3)`
B. `PF_(5),lF_(5)`
C. `C Cl_(4),SF_(4)`
D. `XeF_(2),CO_(2)`

Explanation

To determine the pair of species having identical shapes for their molecules, we need to analyze the given species based on their hybridization and molecular geometry. Let's break down the solution step by step.

### Step 1: Identify the Species
The species given in the question are:
1. BF3 (Boron Trifluoride)
2. PCl3 (Phosphorus Trichloride)
3. PF5 (Phosphorus Pentafluoride)
4. IF5 (Iodine Pentafluoride)
5. CCl4 (Carbon Tetrachloride)
6. SF4 (Sulfur Tetrafluoride)
7. XeF2 (Xenon Difluoride)
8. CO2 (Carbon Dioxide)

### Step 2: Calculate Steric Number and Hybridization
The steric number is calculated using the formula:
\[ \text{Steric Number} = \text{Number of Bond Pairs} + \text{Number of Lone Pairs} \]

#### For BF3:
- Bond pairs = 3 (B-F bonds)
- Lone pairs = 0
- Steric Number = 3 + 0 = 3
- Hybridization = sp²
- Shape = Trigonal Planar

#### For PCl3:
- Bond pairs = 3 (P-Cl bonds)
- Lone pairs = 1
- Steric Number = 3 + 1 = 4
- Hybridization = sp³
- Shape = Trigonal Pyramidal

#### For PF5:
- Bond pairs = 5 (P-F bonds)
- Lone pairs = 0
- Steric Number = 5 + 0 = 5
- Hybridization = sp³d
- Shape = Trigonal Bipyramidal

#### For IF5:
- Bond pairs = 5 (I-F bonds)
- Lone pairs = 1
- Steric Number = 5 + 1 = 6
- Hybridization = sp³d²
- Shape = Square Pyramidal

#### For CCl4:
- Bond pairs = 4 (C-Cl bonds)
- Lone pairs = 0
- Steric Number = 4 + 0 = 4
- Hybridization = sp³
- Shape = Tetrahedral

#### For SF4:
- Bond pairs = 4 (S-F bonds)
- Lone pairs = 1
- Steric Number = 4 + 1 = 5
- Hybridization = sp³d
- Shape = Seesaw

#### For XeF2:
- Bond pairs = 2 (Xe-F bonds)
- Lone pairs = 3
- Steric Number = 2 + 3 = 5
- Hybridization = sp³d
- Shape = Linear

#### For CO2:
- Bond pairs = 2 (C=O bonds)
- Lone pairs = 0
- Steric Number = 2 + 0 = 2
- Hybridization = sp
- Shape = Linear

### Step 3: Compare Shapes
Now, let's compare the shapes of the species:

- BF3: Trigonal Planar
- PCl3: Trigonal Pyramidal
- PF5: Trigonal Bipyramidal
- IF5: Square Pyramidal
- CCl4: Tetrahedral
- SF4: Seesaw
- XeF2: Linear
- CO2: Linear

### Step 4: Identify Identical Shapes
From the analysis, we can see that:
- **XeF2** and **CO2** both have a **Linear** shape.

### Conclusion
The pair of species having identical shapes for molecules of both species is **XeF2 and CO2**.

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