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The charge/size ratio of a cation determ...

The charge/size ratio of a cation determines its polarizing power. Which one of the following sequences represents the increasing order of the polarizing power of the cationic species, `K^(+), Ca^(2+), Mg^(2+), Ba^(2+)`?

A

`Ca^(2+) lt, Ca^(2+) lt Be^(2+) lt K^(+)`

B

`Mg^(2+) lt, Be^(2+) lt K^(+) lt Ca^(2+)`

C

`Be^(2+) lt, K^(+) lt Ca^(+) lt Mg^(2+)`

D

`K^(+) lt, Ca^(2+) lt Mg^(2+) lt Be^(2+)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the increasing order of the polarizing power of the cationic species \( K^+, Ca^{2+}, Mg^{2+}, Ba^{2+} \), we need to consider the charge-to-size ratio of each cation. The polarizing power of a cation is influenced by its charge and size, specifically, it is directly proportional to the charge density, which can be defined as: \[ \text{Charge Density} = \frac{\text{Charge}}{\text{Size}} \] ### Step 1: Identify the charges and sizes of the cations - **Potassium ion (\( K^+ \))**: Charge = +1, relatively large size. - **Calcium ion (\( Ca^{2+} \))**: Charge = +2, smaller than \( K^+ \). - **Magnesium ion (\( Mg^{2+} \))**: Charge = +2, smaller than \( Ca^{2+} \). - **Barium ion (\( Ba^{2+} \))**: Charge = +2, larger than both \( Ca^{2+} \) and \( Mg^{2+} \). ### Step 2: Compare the polarizing power based on charge density 1. **Potassium (\( K^+ \))**: - Charge density is low due to its +1 charge and larger size. 2. **Barium (\( Ba^{2+} \))**: - Charge density is lower than \( Ca^{2+} \) and \( Mg^{2+} \) because although it has a +2 charge, it is larger in size. 3. **Calcium (\( Ca^{2+} \))**: - Charge density is higher than \( Ba^{2+} \) because it has a +2 charge and a smaller size compared to \( Ba^{2+} \). 4. **Magnesium (\( Mg^{2+} \))**: - Charge density is the highest due to its +2 charge and the smallest size among the listed cations. ### Step 3: Establish the increasing order of polarizing power Based on the analysis, we can conclude: - \( K^+ \) has the least polarizing power. - \( Ba^{2+} \) has a higher polarizing power than \( K^+ \) but lower than \( Ca^{2+} \) and \( Mg^{2+} \). - \( Ca^{2+} \) has a higher polarizing power than \( Ba^{2+} \). - \( Mg^{2+} \) has the highest polarizing power. Thus, the increasing order of polarizing power is: \[ K^+ < Ba^{2+} < Ca^{2+} < Mg^{2+} \] ### Final Answer: The correct sequence representing the increasing order of the polarizing power of the cationic species is: \[ K^+ < Ba^{2+} < Ca^{2+} < Mg^{2+} \]

To determine the increasing order of the polarizing power of the cationic species \( K^+, Ca^{2+}, Mg^{2+}, Ba^{2+} \), we need to consider the charge-to-size ratio of each cation. The polarizing power of a cation is influenced by its charge and size, specifically, it is directly proportional to the charge density, which can be defined as: \[ \text{Charge Density} = \frac{\text{Charge}}{\text{Size}} \] ### Step 1: Identify the charges and sizes of the cations ...
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