The pair of compounds having identical shapes for their molecules is:

Options

A. `CH_(4), SF_(4)`
B. `BCl_(3), ClF_(3)`
C. `XeF_(2),ZnCl_(2)`
D. `SO_(2),CO_(2)`

Explanation

To determine the pair of compounds that have identical shapes for their molecules, we need to analyze the molecular geometry of each compound given in the options.

### Step-by-Step Solution:

1. **Identify the Compounds:**
We are given four pairs of compounds to analyze:
- (a) CH₄ and SF₄
- (b) BCl₃ and ClF₃
- (c) XeF₂ and ZnCl₂
- (d) SO₂ and CO₂

2. **Analyze the First Pair (CH₄ and SF₄):**
- **CH₄ (Methane):**
- Carbon has 4 valence electrons and forms 4 single bonds with hydrogen.
- Steric number = 4 (4 bond pairs, 0 lone pairs).
- Hybridization = sp³.
- Shape = Tetrahedral.

- **SF₄ (Sulfur Tetrafluoride):**
- Sulfur has 6 valence electrons and forms 4 single bonds with fluorine and has 1 lone pair.
- Steric number = 5 (4 bond pairs, 1 lone pair).
- Hybridization = sp³d.
- Shape = Seesaw.

**Conclusion:** Different shapes.

3. **Analyze the Second Pair (BCl₃ and ClF₃):**
- **BCl₃ (Boron Trichloride):**
- Boron has 3 valence electrons and forms 3 single bonds with chlorine.
- Steric number = 3 (3 bond pairs, 0 lone pairs).
- Hybridization = sp².
- Shape = Trigonal planar.

- **ClF₃ (Chlorine Trifluoride):**
- Chlorine has 7 valence electrons and forms 3 single bonds with fluorine and has 2 lone pairs.
- Steric number = 5 (3 bond pairs, 2 lone pairs).
- Hybridization = sp³d.
- Shape = T-shaped.

**Conclusion:** Different shapes.

4. **Analyze the Third Pair (XeF₂ and ZnCl₂):**
- **XeF₂ (Xenon Difluoride):**
- Xenon has 8 valence electrons and forms 2 single bonds with fluorine and has 3 lone pairs.
- Steric number = 5 (2 bond pairs, 3 lone pairs).
- Hybridization = sp³d.
- Shape = Linear (due to lone pairs).

- **ZnCl₂ (Zinc Chloride):**
- Zinc has 2 valence electrons and forms 2 single bonds with chlorine.
- Steric number = 2 (2 bond pairs, 0 lone pairs).
- Hybridization = sp.
- Shape = Linear.

**Conclusion:** Both have the same shape (Linear).

5. **Analyze the Fourth Pair (SO₂ and CO₂):**
- **SO₂ (Sulfur Dioxide):**
- Sulfur has 6 valence electrons and forms 2 double bonds with oxygen and has 1 lone pair.
- Steric number = 3 (2 bond pairs, 1 lone pair).
- Hybridization = sp².
- Shape = Bent or Angular.

- **CO₂ (Carbon Dioxide):**
- Carbon has 4 valence electrons and forms 2 double bonds with oxygen.
- Steric number = 2 (2 bond pairs, 0 lone pairs).
- Hybridization = sp.
- Shape = Linear.

**Conclusion:** Different shapes.

### Final Answer:
The pair of compounds having identical shapes for their molecules is **(c) XeF₂ and ZnCl₂**.