L.C.A.O. Principle is involved in the formationof the molecular orbitals according ot molecular orbital theory. The energy of the bonding molecular orbital is less than that of thecombining atomic orbitals while that of the antibonding molecular orbitals while that of the order `(B.O.)=1/2(N_(b)-N_(a))` helps in predicting (i) formation of molecules/molecular ions, bond dossociation energy, stability and bond length. Only the molecules or ions with positive B.O. can be formed. These will be diamagnetic if all molecular orbitals are dilled and paramagnetic if one of more are half filled. The atomic prbitals at the time of overlap must have the same symmetry as well.
Bond arder is :
L.C.A.O. Principle is involved in the formationof the molecular orbitals according ot molecular orbital theory. The energy of the bonding molecular orbital is less than that of thecombining atomic orbitals while that of the antibonding molecular orbitals while that of the order `(B.O.)=1/2(N_(b)-N_(a))` helps in predicting (i) formation of molecules/molecular ions, bond dossociation energy, stability and bond length. Only the molecules or ions with positive B.O. can be formed. These will be diamagnetic if all molecular orbitals are dilled and paramagnetic if one of more are half filled. The atomic prbitals at the time of overlap must have the same symmetry as well.
Bond arder is :
Bond arder is :
A
directly related to bond length
B
inversely related to bond length
C
incersely related to bond strength
D
never fractional.
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AI Generated Solution
The correct Answer is:
To solve the question regarding bond order and its relationship with bond length and bond strength, we will follow these steps:
### Step-by-Step Solution:
1. **Understanding Bond Order (B.O.):**
- Bond order is defined as the difference between the number of bonding electrons (N_b) and the number of antibonding electrons (N_a), divided by two. The formula is given as:
\[
\text{Bond Order (B.O.)} = \frac{1}{2}(N_b - N_a)
\]
2. **Relationship Between Bond Order and Bond Length:**
- Bond order is inversely related to bond length. This means that as the bond order increases, the bond length decreases. A higher bond order indicates a stronger bond, which typically results in shorter bond lengths.
3. **Relationship Between Bond Order and Bond Strength:**
- Bond order is directly proportional to bond strength. This means that a higher bond order corresponds to a stronger bond. For example, a triple bond has a higher bond order (3) than a double bond (2), and is therefore stronger.
4. **Fractional Bond Order:**
- It is important to note that bond order can be fractional. This occurs in cases where there are resonance structures or when dealing with certain molecular ions where the distribution of electrons does not lead to whole number bond orders.
5. **Conclusion:**
- Based on the above relationships:
- Bond order is inversely related to bond length.
- Bond order is directly related to bond strength.
- Bond order can be fractional.
### Final Answer:
Given the options provided, the correct answer is:
- **Bond order is inversely related to bond length.** (Option B)
To solve the question regarding bond order and its relationship with bond length and bond strength, we will follow these steps:
### Step-by-Step Solution:
1. **Understanding Bond Order (B.O.):**
- Bond order is defined as the difference between the number of bonding electrons (N_b) and the number of antibonding electrons (N_a), divided by two. The formula is given as:
\[
\text{Bond Order (B.O.)} = \frac{1}{2}(N_b - N_a)
...
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L.C.A.O. Principle is involved in the formation of the molecular orbitals according to molecular orbital theory. The energy of the bonding molecular orbital is less than that of the combining atomic orbitals while that of the antibonding molecular orbitals while that of the order (B.O.)=1/2(N_(b)-N_(a)) helps in predicting (i) formation of molecules/molecular ions, bond dissociation energy, stability and bond length. Only the molecules or ions with positive B.O. can be formed. These will be diamagnetic if all molecular orbitals are dilled and paramagnetic if one of more are half filled. The atomic orbitals at the time of overlap must have the same symmetry as well. The bond order (B.O.) in B_(2) molecule is:
L.C.A.O. Principle is involved in the formation of the molecular orbitals according to molecular orbital theory. The energy of the bonding molecular orbital is less than that of the combining atomic orbitals while that of the antibonding molecular orbitals while that of the order (B.O.)=1/2(N_(b)-N_(a)) helps in predicting (i) formation of molecules/molecular ions, bond dissociation energy, stability and bond length. Only the molecules or ions with positive B.O. can be formed. These will be diamagnetic if all molecular orbitals are dilled and paramagnetic if one of more are half filled. The atomic orbitals at the time of overlap must have the same symmetry as well. In the homonuclear molecule which of the following sets of M.O. orbitals are degenerate ?
L.C.A.O. Principle is involved in the formation of the molecular orbitals according to molecular orbital theory. The energy of the bonding molecular orbital is less than that of the combining atomic orbitals while that of the antibonding molecular orbitals while that of the order (B.O.)=1/2(N_(b)-N_(a)) helps in predicting formation of molecules/molecular ions, bond dissociation energy, stability and bond length. Only the molecules or ions with positive B.O. can be formed. These will be diamagnetic if all molecular orbitals are dilled and paramagnetic if one of more are half filled. The atomic orbitals at the time of overlap must have the same symmetry as well. In the formation of N_(2)^(+) from N_(2), the electron is removed from a
According to molecular orbital theory,
According to Molecular Orbital Theory,
L.C.A.O. principle is involved in the formation of molecular orbitals according to molecular obtital theory. The energy of bonding molecular orbital is less than that of the combining atomic orbitals while that of the anitibonding bonding melecular orbital is more. The B.O. =^(1//2)[N_(b)-N_(a)] Answer the following questions on the basis of the above paragraph : (i) What is bonding molecular orbital ? (ii) Calculate B.O. of He_(2) molecule.
According to molecular orbital theory which of the following is correct :
How is bonding molecular orbital of hydrogen different from the antibonding molecular orbital ?
Explain bonding and antibonding molecular orbitals.
A bonding molecular orbital is formed when the electron waves of the combining atoms are in phase.
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