The shapes of `XeO_(2)F_(2)` molecule is

Options

A. trigonal bipyramidal
B. square planar
C. tetrahedral
D. see-saw.

Explanation

To determine the shape of the molecule \( \text{XeO}_2\text{F}_2 \), we can follow these steps:

### Step 1: Identify the central atom and its valence electrons
- The central atom in the molecule is Xenon (Xe), which is a noble gas in Group 18 of the periodic table.
- Xenon has 8 valence electrons.

### Step 2: Determine the number of bonds and lone pairs
- In \( \text{XeO}_2\text{F}_2 \), Xenon is bonded to two oxygen atoms and two fluorine atoms.
- This gives a total of 4 bonding pairs (2 from O and 2 from F).
- Since Xenon has 8 valence electrons and is using 4 for bonding, it will have \( 8 - 4 = 4 \) electrons left, which means there are 2 lone pairs of electrons.

### Step 3: Apply the VSEPR theory
- According to VSEPR (Valence Shell Electron Pair Repulsion) theory, we need to consider both bonding pairs and lone pairs.
- The total number of electron pairs around the central atom (Xenon) is \( 4 \) (bonding pairs) + \( 2 \) (lone pairs) = \( 6 \) electron pairs.

### Step 4: Determine the molecular geometry
- With 6 electron pairs, the electron geometry is octahedral.
- However, the presence of lone pairs affects the molecular shape. The lone pairs will occupy positions that minimize repulsion, which typically are in the equatorial positions of the octahedral arrangement.

### Step 5: Identify the final shape
- The molecular shape of \( \text{XeO}_2\text{F}_2 \) is derived from the octahedral arrangement with 2 lone pairs. This results in a "square planar" shape or a "distorted tetrahedral" arrangement, often referred to as "SES" (Square Planar Electron Shell).

### Final Answer
The shape of the \( \text{XeO}_2\text{F}_2 \) molecule is **Square Planar** or **SES**.

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