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Iso-structural species among the followi...

Iso-structural species among the following are `(l) CH_(3)^(+)(ll)H_(3)O^(+)(lll)NH_(3)(IV)CH_(3)^(-)`

A

l and ll

B

lll and IV

C

l and lll

D

ll,lll and lV

Text Solution

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The correct Answer is:
To determine the isostructural species among the given compounds, we need to analyze the molecular geometry and hybridization of each species. ### Step-by-Step Solution: 1. **Identify the Species:** The species given are: - (I) \( CH_3^+ \) - (II) \( H_3O^+ \) - (III) \( NH_3 \) - (IV) \( CH_3^- \) 2. **Analyze \( CH_3^+ \):** - Carbon has 4 valence electrons. In \( CH_3^+ \), one electron is removed due to the positive charge. - This results in 3 bond pairs and no lone pairs. - The hybridization is \( sp^2 \) and the shape is **trigonal planar**. 3. **Analyze \( H_3O^+ \):** - Oxygen has 6 valence electrons. In \( H_3O^+ \), one electron is removed. - This results in 3 bond pairs and 1 lone pair. - The hybridization is \( sp^3 \) and the shape is **pyramidal**. 4. **Analyze \( NH_3 \):** - Nitrogen has 5 valence electrons. In \( NH_3 \), it has 3 bond pairs and 1 lone pair. - The hybridization is \( sp^3 \) and the shape is **pyramidal**. 5. **Analyze \( CH_3^- \):** - Carbon has 4 valence electrons. In \( CH_3^- \), there is one extra electron. - This results in 3 bond pairs and 1 lone pair. - The hybridization is \( sp^3 \) and the shape is **pyramidal**. 6. **Compare the Structures:** - \( CH_3^+ \) is **trigonal planar** (with \( sp^2 \) hybridization). - \( H_3O^+ \), \( NH_3 \), and \( CH_3^- \) are all **pyramidal** (with \( sp^3 \) hybridization). ### Conclusion: The isostructural species among the given options are: - \( H_3O^+ \) (II) - \( NH_3 \) (III) - \( CH_3^- \) (IV)
To determine the isostructural species among the given compounds, we need to analyze the molecular geometry and hybridization of each species. ### Step-by-Step Solution: 1. **Identify the Species:** The species given are: - (I) \( CH_3^+ \) - (II) \( H_3O^+ \) ...
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