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Hydrogen bonds are formed in many compou...

Hydrogen bonds are formed in many compounds e.g. `H_(2)O`, HF, `NH_(3)`. The boiling point of such compounds depends to a extent on the strength of hydrogen bond and the number of hydrogen bonds. The correct decreasing order of the boiling points above compounds is

A

`HF gt H_(2)O gt NH_(3)`

B

`N_(2)O gt HF gt NH_(3)`

C

`NH_(3) gt HF gt H_(2)O`

D

`NH_(3) gt H_(2)O gt HF`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the correct decreasing order of boiling points for the compounds H₂O, HF, and NH₃, we need to analyze the strength and number of hydrogen bonds formed in each compound. ### Step-by-Step Solution: 1. **Identify the Compounds and Their Hydrogen Bonding:** - The compounds in question are water (H₂O), hydrogen fluoride (HF), and ammonia (NH₃). - Each of these compounds can form hydrogen bonds due to the presence of hydrogen atoms bonded to highly electronegative atoms (O, F, N). 2. **Strength of Hydrogen Bonds:** - The strength of hydrogen bonds varies based on the electronegativity of the atoms involved: - HF has the strongest hydrogen bonds because fluorine is the most electronegative element. - H₂O has strong hydrogen bonds as oxygen is also highly electronegative but less so than fluorine. - NH₃ has the weakest hydrogen bonds among these three because nitrogen is less electronegative than both oxygen and fluorine. 3. **Number of Hydrogen Bonds:** - Water (H₂O) can form four hydrogen bonds per molecule due to its bent structure and the presence of two lone pairs on oxygen. - Hydrogen fluoride (HF) can form two hydrogen bonds per molecule (one with another HF molecule). - Ammonia (NH₃) can form three hydrogen bonds per molecule, but the overall strength is lower than that of water and HF. 4. **Comparing Boiling Points:** - The boiling point of a substance is influenced by both the strength and the number of hydrogen bonds. - Given that water can form the most hydrogen bonds and has strong hydrogen bonding, it has the highest boiling point. - HF, while having strong hydrogen bonds, has fewer hydrogen bonds than water, resulting in a lower boiling point. - NH₃ has the weakest hydrogen bonds and fewer hydrogen bonds compared to water and HF, giving it the lowest boiling point. 5. **Conclusion:** - Based on the analysis, the correct decreasing order of boiling points for the compounds is: - H₂O > HF > NH₃ ### Final Answer: The correct decreasing order of boiling points is: **H₂O > HF > NH₃**

To determine the correct decreasing order of boiling points for the compounds H₂O, HF, and NH₃, we need to analyze the strength and number of hydrogen bonds formed in each compound. ### Step-by-Step Solution: 1. **Identify the Compounds and Their Hydrogen Bonding:** - The compounds in question are water (H₂O), hydrogen fluoride (HF), and ammonia (NH₃). - Each of these compounds can form hydrogen bonds due to the presence of hydrogen atoms bonded to highly electronegative atoms (O, F, N). ...
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