The electronic configuration of the outer most shell of the most electronegative element is :

Options

A. `2s^(2)2p^(5)`
B. `3s^(2)3p^(5)`
C. `4s^(2)4p^(5)`
D. `5s^(2)5p^(5)`

Explanation

To find the electronic configuration of the outermost shell of the most electronegative element, we can follow these steps:

### Step 1: Identify the Most Electronegative Element
The most electronegative element in the periodic table is fluorine (F). It is located in Group 17 (the halogens) and is known for its high electronegativity.

**Hint:** Remember that electronegativity decreases as you move down a group in the periodic table.

### Step 2: Determine the Electronic Configuration of Fluorine
Fluorine has an atomic number of 9. The electronic configuration of fluorine can be written as:
- 1s² 2s² 2p⁵

This means that the outermost shell (the second shell) has:
- 2 electrons in the 2s subshell
- 5 electrons in the 2p subshell

**Hint:** The outermost shell is determined by the highest principal quantum number (n).

### Step 3: Identify the Outermost Shell Configuration
The outermost shell configuration for fluorine is the combination of the 2s and 2p subshells:
- Outermost shell configuration: 2s² 2p⁵

**Hint:** Look for the highest energy level (n) to find the outermost shell.

### Conclusion
Thus, the electronic configuration of the outermost shell of the most electronegative element (fluorine) is:
- **2s² 2p⁵**