Home
Class 11
CHEMISTRY
A flask was heated from 27^(@)C to 227^(...

A flask was heated from `27^(@)C` to `227^(@)C` at constant pressure. Calculate the volume of the flask if `0.1 dm^(3)` of air measured at `27^(@)C` was expelled from the flask.

Text Solution

AI Generated Solution

To solve the problem, we will use Charles's Law, which states that at constant pressure, the volume of a gas is directly proportional to its temperature in Kelvin. The formula for Charles's Law is: \[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \] ### Step-by-Step Solution: ...
Promotional Banner

Similar Questions

Explore conceptually related problems

300 ml of a gas at 27^(@)C is cooled to -3^(@)C at constant pressure, the final volume is

A flask of capacity 2 L is heated from 35 C^(@) to 45 C^(@) . What volume of air will escape from the flask ?

An open flask at 25^@C contains air. Calculate the temperature at which one fifth of air measured at 25^@C escapes.

A flask of capacity 3 L is heated from 25^∘ C to 35^∘ C. What volume of air will escape from the flask?

A perfect gas at 27^(@)C is heated at constant pressure so as to duble its volume. The tmemperature of th gas will be

A flask of capacity 4 L is heated from 35^∘ C to 45^∘ C. What volume of air will escape from the flask?

An open flask contains air at 27^(@)C Calculate the temperature at which it should be heated so that (1)/(3) rd of air measured at 27^(@)C escapes out

Aperfect gas at 27^(@) C is heated at constant pressure soas to duuble its volume. The increase in temperature of the gas will be

A perfect gas at 27^(@)C is heated at constant pressure so as to triple its volume. The tmemperature of th gas will be

A perfect gas at 27^(@)C is heated at constant pressure so as to triple its volume. The tmemperature of th gas will be