`200 mL` of `SO_(2)` diffuse through a porous plug in 600 seconds. What volume of methane `(CH_(4))` will diffuse in the same time ?

Explanation

To solve the problem of how much volume of methane (CH₄) will diffuse through a porous plug in the same time as 200 mL of sulfur dioxide (SO₂), we can use Graham's law of effusion. This law states that the rate of diffusion of a gas is inversely proportional to the square root of its molar mass.

### Step-by-Step Solution:

1. **Identify Given Values:**
- Volume of SO₂ (V₁) = 200 mL
- Time (t) = 600 seconds
- Molar mass of SO₂ (M₁) = 64 g/mol (calculated from 32 g/mol for S and 16 g/mol for O)
...