A vessel of 120 mL capacity contains a certain amount of gas at `35 ^(@)C` and 1.2 bar pressure. The gas is transferred to another vessel of volume 180 mL at `35 ^(@)C.` What would be its pressure?

Explanation

From the given data : `P_(1) = 1.2 "bar" , P_(2) = ?`
`V_(1) = 120 mL , V_(2) = 180 mL`
Since temperature is constant, boyles Law can be applied.
`P_(1)V_(1) = P_(2)V_(2)` or `P_(2) = (P_(1)V_(1))/(P_(2)), P_(2) = ((1.2 "bar") xx (120 mL))/((180 mL)) = 0.8` bar