calculte the total number of electrons present 1.4 g of dinitrogen gas.

Explanation

Molecular mass of `N_(2) = 28 g`
`28 g` of `N_(2)` represent molecules `= 6.022 xx 10^(23)`
`1.4 g` of `N_(2)` of represent molecules `= 6.022 xx 10^(23) xx ((1.4 g))/((28 g)) = 3.011 xx 10^(22)` molecules
Atomic number of nitrogen `(N) = 7`
`1` molecules of `N_(2)` bar has electrons `= 7 xx 2 = 14`
`3.011 xx 10^(22)` molecules of `N_(2)` have electrons `= 4 xx 3.011 xx 10^(22) = 4.215 xx 10^(23)` electrons