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At what temperature in degree centigrade...

At what temperature in degree centigrade will the volume of a gas, which is originally at `0^@C`, double itself, pressure remaining constant.

Text Solution

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The correct Answer is:
`273^(@)C`
`V_(1) = V mL , V_(2) = mL`
`T_(2) = 0 + 273 = 297 K` , `T_(2) = -30 + 273 = 243 K`
Since pressure of the gas is constant, Charles' Law is applicable.
`(V_(1))/(T_(1)) = (V_(2))/(T_(2))` or `T_(2) = (V_(2) xx T_(1))/(V_(1)) = ((2 V mL) xx (273 K))/((V mL)) = 546 K = 273^(@)C`.
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