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50 mL of each gas A and of gas B takes 1...

50 mL of each gas A and of gas B takes 150 and 200 s respectively for effusing through a pin hole under the similar conditions. If molecular mass of gas B is 36, the molecular mass of gas A will be

A

95

B

128

C

20

D

64

Text Solution

Verified by Experts

The correct Answer is:
C
`r_(A) = (V_(A))/(t_(A)) = 50/150`
`r_(B) = (V_(B))/(t_(B)) = 50/200`
According to Graham's Law of effusion
`(r_(A))/(r_(B)) = sqrt( M_(B))/(M_(A))`
`(200)/(150) = sqrt((36)/(M_(A))` or `M_(A) = (36 xx 150 xx 150)/(200 xx 200)`
`M_(B) = 2.25 ~~ 20`.
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