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A certain gas takes three times as long ...

A certain gas takes three times as long to effuse out as helium. Its molecular mass will be

A

27u

B

36u

C

64u

D

9u.

Text Solution

Verified by Experts

The correct Answer is:
B
According to Graham's Law of effusion,
`(t_("gas"))/(t_("He")) = sqrt((M_("gas"))/(M_("He")))` or `3 = sqrt((M_("gas"))/(4 u))`
`M_("gas") = 3 xx 3 xx 4 = 36 u`.
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