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Equal weights of methane and oxygen are ...

Equal weights of methane and oxygen are mixed in an empty container at `25^(@)C`. The fraction of the total pressure exerted by oxygen is

A

`1/3`

B

`1/2`

C

`2/3`

D

`1/3 xx 273/298`.

Text Solution

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The correct Answer is:
To solve the problem of finding the fraction of the total pressure exerted by oxygen when equal weights of methane (CH₄) and oxygen (O₂) are mixed in an empty container at 25°C, we can follow these steps: ### Step 1: Define the masses of the gases Let the mass of methane (CH₄) be \( m_{CH4} = X \) grams. Since equal weights are mixed, the mass of oxygen (O₂) will also be \( m_{O2} = X \) grams. ### Step 2: Calculate the number of moles of each gas To find the number of moles, we use the formula: \[ \text{Moles} = \frac{\text{Mass}}{\text{Molar Mass}} \] - For methane (CH₄): - Molar mass of CH₄ = 16 g/mol - Moles of CH₄ = \( \frac{X}{16} \) - For oxygen (O₂): - Molar mass of O₂ = 32 g/mol - Moles of O₂ = \( \frac{X}{32} \) ### Step 3: Calculate the total number of moles The total number of moles in the mixture is the sum of the moles of methane and oxygen: \[ \text{Total moles} = \text{Moles of CH₄} + \text{Moles of O₂} = \frac{X}{16} + \frac{X}{32} \] To add these fractions, we need a common denominator: - The least common multiple of 16 and 32 is 32. - Convert \( \frac{X}{16} \) to \( \frac{2X}{32} \). Now we can add: \[ \text{Total moles} = \frac{2X}{32} + \frac{X}{32} = \frac{3X}{32} \] ### Step 4: Calculate the mole fraction of oxygen The mole fraction of oxygen (χ_O₂) is given by: \[ \chi_{O₂} = \frac{\text{Moles of O₂}}{\text{Total moles}} = \frac{\frac{X}{32}}{\frac{3X}{32}} = \frac{1}{3} \] ### Step 5: Calculate the fraction of total pressure exerted by oxygen According to Dalton's law of partial pressures, the partial pressure of a gas is equal to its mole fraction multiplied by the total pressure: \[ P_{O₂} = \chi_{O₂} \times P_{total} \] The fraction of the total pressure exerted by oxygen is simply its mole fraction: \[ \text{Fraction of total pressure by O₂} = \chi_{O₂} = \frac{1}{3} \] ### Conclusion The fraction of the total pressure exerted by oxygen is \( \frac{1}{3} \). ---

To solve the problem of finding the fraction of the total pressure exerted by oxygen when equal weights of methane (CH₄) and oxygen (O₂) are mixed in an empty container at 25°C, we can follow these steps: ### Step 1: Define the masses of the gases Let the mass of methane (CH₄) be \( m_{CH4} = X \) grams. Since equal weights are mixed, the mass of oxygen (O₂) will also be \( m_{O2} = X \) grams. ### Step 2: Calculate the number of moles of each gas To find the number of moles, we use the formula: \[ ...
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