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Statement-1. Vapour pressure of liquid a...

Statement-1. Vapour pressure of liquid ammonia is more than that of water.
Statement-2. Molar mass of ammonia is less than that of water.

A

Statement-1 is true, statement-2 is also true, statement-2 is correct explanation of statement-1

B

Statement-1 is true, statement-2 is also true, statement-2 is not correct explanation of statement-1

C

Statement-1 is true, statement-2 is true.

D

Statement-1 is false, statement-2 is true.

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the statements provided in the question, we will evaluate each statement step by step. ### Step 1: Analyze Statement-1 **Statement-1:** Vapour pressure of liquid ammonia is more than that of water. - **Vapour Pressure and Hydrogen Bonding:** Vapour pressure is inversely related to the strength of hydrogen bonding in a liquid. The stronger the hydrogen bonding, the lower the vapour pressure. - **Comparison of Hydrogen Bonding:** - Water (H₂O) has a high degree of hydrogen bonding due to the high electronegativity of oxygen, which can form up to four hydrogen bonds with surrounding water molecules. - Ammonia (NH₃) has hydrogen bonding as well, but the nitrogen atom is less electronegative than oxygen, resulting in weaker hydrogen bonds compared to water. **Conclusion for Statement-1:** Since water has stronger hydrogen bonding than ammonia, it will have a lower vapour pressure. Therefore, the statement that the vapour pressure of liquid ammonia is more than that of water is **true**. ### Step 2: Analyze Statement-2 **Statement-2:** Molar mass of ammonia is less than that of water. - **Calculate Molar Mass:** - Molar mass of ammonia (NH₃): Nitrogen (N) has a molar mass of approximately 14 g/mol, and each hydrogen (H) has a molar mass of about 1 g/mol. Therefore, the molar mass of ammonia is: \[ \text{Molar mass of NH₃} = 14 + (3 \times 1) = 17 \text{ g/mol} \] - Molar mass of water (H₂O): Oxygen (O) has a molar mass of approximately 16 g/mol, and two hydrogens contribute: \[ \text{Molar mass of H₂O} = 16 + (2 \times 1) = 18 \text{ g/mol} \] **Conclusion for Statement-2:** Since the molar mass of ammonia (17 g/mol) is indeed less than that of water (18 g/mol), this statement is also **true**. ### Final Conclusion Both statements are true: - Statement-1 is true because the vapour pressure of ammonia is higher than that of water due to weaker hydrogen bonding. - Statement-2 is true because the molar mass of ammonia is less than that of water. However, the second statement does not provide a correct explanation for the first statement.

To analyze the statements provided in the question, we will evaluate each statement step by step. ### Step 1: Analyze Statement-1 **Statement-1:** Vapour pressure of liquid ammonia is more than that of water. - **Vapour Pressure and Hydrogen Bonding:** Vapour pressure is inversely related to the strength of hydrogen bonding in a liquid. The stronger the hydrogen bonding, the lower the vapour pressure. - **Comparison of Hydrogen Bonding:** - Water (H₂O) has a high degree of hydrogen bonding due to the high electronegativity of oxygen, which can form up to four hydrogen bonds with surrounding water molecules. ...
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