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CH(3)-CH=CH(2)underset("Peroxide")overse...

`CH_(3)-CH=CH_(2)underset("Peroxide")overset(HBr)to[A]overset(KOH(aq))to[B]underset(443 K)overset(H_(2)SO_(4)(conc.))to[C]`

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To solve the given question step by step, we will follow the reactions involving the compound CH₃-CH=CH₂ (propene) as it undergoes various transformations. ### Step 1: Reaction of Propene with HBr in the presence of Peroxide - **Starting Compound**: Propene (CH₃-CH=CH₂) - **Reagent**: HBr (Hydrobromic acid) in the presence of peroxide - **Mechanism**: The presence of peroxide leads to the anti-Markovnikov addition of HBr to the alkene. According to anti-Markovnikov's rule, the bromine (Br) will attach to the carbon with more hydrogens (the terminal carbon), while hydrogen (H) will attach to the other carbon. - **Product A**: The major product formed is bromopropane (CH₃-CHBr-CH₃). ...
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CH_(3)-underset(CH_(3)) underset(|) (C)= CH_(2) underset("Peroxide") overset(HBr)to CH_(3)-underset(CH_(3)) underset(|) (CH)-CH_(2)Br reaction intermediate of this reaction is:

When pinacol is treated with dilute H_(2)SO_(4) , a re-arangement reaction takes place which leads to the formation of a ketone. CH_(3)-underset(CH_(3))underset(|)overset(OH)overset(|)C-underset(CH_(3))underset(|)overset(OH)C-CH_(3)overset(H_(2)SO_(4))rarrCH_(3)-underset(CH_(3))underset(|)overset(O)overset(||)C-overset(CH_(3))overset(|)C-CH_(5) This reaction involves re-arrangement of carbocation Step 1: CH_(3)-underset(CH_(3))underset(|)overset(OH)overset(|)C-underset(CH_(3))overset(+)overset(OH_(2))overset(|)C-CH_(2)rarrCH_(3)-underset(CH_(3))underset(|)overset(OH)overset(|)C-underset(CH_(3))underset(|)overset(OH)overset(|)C-underset(CH_(3))underset(|)overset(+)C-CH_(3) Step 2: Carbocation rearrange by hydride, alkyl shift to get as stable as they can. Stability is the driving force for re-arrangement migration of bond may also oC Cur. Where by ring expansion and ring contraction takes place. The relief of strain can provide a powerful driving force for re-arrangement. What will be the product of following reaction R is:

When pinacol is treated with dilute H_(2)SO_(4) , a re-arangement reaction takes place which leads to the formation of a ketone. CH_(3)-underset(CH_(3))underset(|)overset(OH)overset(|)C-underset(CH_(3))underset(|)overset(OH)C-CH_(3)overset(H_(2)SO_(4))rarrCH_(3)-underset(CH_(3))underset(|)overset(O)overset(||)C-overset(CH_(3))overset(|)C-CH_(5) This reaction involves re-arrangement of carbocation Step 1: CH_(3)-underset(CH_(3))underset(|)overset(OH)overset(|)C-underset(CH_(3))overset(+)overset(OH_(2))overset(|)C-CH_(2)rarrCH_(3)-underset(CH_(3))underset(|)overset(OH)overset(|)C-underset(CH_(3))underset(|)overset(OH)overset(|)C-underset(CH_(3))underset(|)overset(+)C-CH_(3) Step 2: Carbocation rearrange by hydride, alkyl shift to get as stable as they can. Stability is the driving force for re-arrangement migration of bond may also oC Cur. Where by ring expansion and ring contraction takes place. The relief of strain can provide a powerful driving force for re-arrangement. What will be the product of following reaction

The IUPAC name of following compound is: CH_(3)CH_(2) - underset(CH_(3))underset(|)overset(H)overset(|)(C) - underset(CH_(3))underset(|)overset(C_(4)H_(9))overset(|)(C) - CH_(3)