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Using curved arrow notation show the for...

Using curved arrow notation show the formation of reaction intermediates when the following covalent bonds undergo heterolysis.
(i) `H_(3)C-CH_(2)-Cl" "`(ii) `H_(3)C-C equiv N" "`(iii) `CH_(3)ONa`

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To solve the question of showing the formation of reaction intermediates when the given covalent bonds undergo heterolysis, we will follow these steps for each compound: ### Step 1: Understanding Heterolysis Heterolysis is the process where a covalent bond breaks and one atom takes both electrons, resulting in the formation of a cation and an anion. The more electronegative atom will attract the electrons towards itself. ### Step 2: Analyzing the Compounds We will analyze each compound provided in the question and depict the heterolysis using curved arrow notation. ...
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