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In Duma's method 0.206 g of an organic c...

In Duma's method 0.206 g of an organic compound gave `18.8 cm^(3)` of moist `N_(2)` at `17^(@)C` and 760 mm Hg pressure. If aqueous at `17^(@)C` is 14.5 mm Hg, calculate the percentage of nitrogen in the given organic compound.

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To calculate the percentage of nitrogen in the given organic compound using Duma's method, we will follow these steps: ### Step 1: Determine the pressure of the dry nitrogen gas The total pressure is given as 760 mm Hg, and the vapor pressure of water at 17°C is 14.5 mm Hg. Therefore, the pressure of the dry nitrogen gas can be calculated as: \[ P_1 = P_{\text{total}} - P_{\text{water}} = 760 \, \text{mm Hg} - 14.5 \, \text{mm Hg} = 745.5 \, \text{mm Hg} \] ...
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