In the organic compound `CH_(2)=CH-CH_(2)-CH_(2)-C equiv CH`, the `CH-CH_(2)` bond is formed by the interaction of a pair of hybridised orbitals :

Options

A. `sp-sp^(2)`
B. `sp-sp^(3)`
C. `sp^(2)-sp^(3)`
D. `sp^(3)-sp^(3)`.

Explanation

To determine the hybridization of the carbon atoms involved in the bond between `CH` and `CH2` in the compound `CH2=CH-CH2-CH2-C≡CH`, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Structure**:
The compound can be represented as:
```
CH2=CH-CH2-CH2-C≡CH
```
We need to focus on the bond between the `CH` (which is part of the `CH2`) and the `CH2` group.

2. **Identify the Relevant Carbons**:
The two carbons we are interested in are:
- The carbon in `CH2` (which is sp2 hybridized due to the double bond with the adjacent carbon).
- The carbon in `CH` (which is part of the `CH2` group).

3. **Determine the Hybridization of Each Carbon**:
- For the carbon in `CH2`:
- It forms 3 sigma bonds (2 with hydrogen and 1 with the adjacent carbon).
- The steric number is 3 (3 sigma bonds).
- Therefore, the hybridization is **sp2**.

- For the carbon in `CH`:
- It forms 4 sigma bonds (1 with hydrogen and 3 with the adjacent carbon).
- The steric number is 4 (4 sigma bonds).
- Therefore, the hybridization is **sp3**.

4. **Determine the Type of Bond Formed**:
The bond between the `CH` and `CH2` is formed by the overlap of the hybridized orbitals:
- The `sp2` hybridized orbital from the `CH2` carbon overlaps with the `sp3` hybridized orbital from the `CH` carbon.

5. **Conclusion**:
The bond between `CH` and `CH2` is formed by the interaction of an **sp2 hybridized orbital from the `CH2` carbon and an sp3 hybridized orbital from the `CH` carbon**.

### Final Answer:
The `CH-CH2` bond is formed by the interaction of a pair of hybridized orbitals: **sp2 and sp3**.