Home
Class 11
CHEMISTRY
In Carius method of estimation of haloge...

In Carius method of estimation of halogen, 0.15 g of an organic compound gave 0.12 g of AgBr. Find out the percentage of bromine in the compound.

Text Solution

Verified by Experts

The correct Answer is:
`34.0`
Percentage of bromine `=80/188xx ("Mass of AgBr")/("Mass of compound")xx100=80/188xx0.12/0.15xx100=34%`
Promotional Banner

Similar Questions

Explore conceptually related problems

In Carium method of estimation of halgoen, 0.15 g of an organic compound gave 0.12 g of AgBr. What is the percentage of bromine in the compound?

In the Carius method of estimation of halogen. 0.25 g of an organic compound gave 0.188 g of AgBr. The percentage of bromine in the compound is (Molar mass of AgBr = 188 g mol^-1 )

In the Carius method of estimation of halogens, 0.250 g of an organic compound gives 0.141 g of AgBr Calculate the percentage of bromine in the compound. (At. wt. of Ag= 108, Br= 80).

In Carius method of estimation of halogens 250 mg of an organic compound gave 141 mg of AgBr . The percentage of bromine in the compound is (atomic mass Ag = 108, Br = 80 )

In Carius method, 0.18 gram of an organic compound gave 0.11 gram of AgBr. The percentage of Br in the compound is

0.4 g of Organic Compound gave 0.188g of AgBr. The percentage of Br in the compound is

In an estimation of bromine by Carius method , 1.6 g of an organic compound gave 1.88 g of AgBr . The mass percentage of bromine in the compound is ________ ( Atomic mass , Ag=108 , Br = 80 g "mol"^(-1) )

In sulphur estimation, 0.157 g of an organic compound gave 0.4813 g of barium sulphate. What is the percentage of sulphur in the compound?

1.6 g of an organic compound gave 2.6 g of magnesium pyrophosphate. The percentage of phosphorus in the compound is

0.15 gm of an organic compound gave 0.12 gm of silver bromide by the carius method. Find the percentage of bromine in the compound.