Home
Class 11
CHEMISTRY
0.3160 g of an organic substance was hea...

0.3160 g of an organic substance was heated with fuming nitric acid in a carius tube to convert phosphorus present into phosphoric acid. Addition of magnesia mixture formed `MgNH_(4)PO_(4)` which upon heating gave `0.1697 g Mg_(2)P_(2)O_(7)`. Calculate the percentage of phosphorus in the compound.

Text Solution

AI Generated Solution

The correct Answer is:
To calculate the percentage of phosphorus in the organic compound, we will follow these steps: ### Step 1: Determine the molar mass of \( \text{Mg}_2\text{P}_2\text{O}_7 \) 1. **Calculate the molar mass of each element in the compound:** - Magnesium (Mg): \( 24 \, \text{g/mol} \) - Phosphorus (P): \( 31 \, \text{g/mol} \) - Oxygen (O): \( 16 \, \text{g/mol} \) 2. **Calculate the total molar mass of \( \text{Mg}_2\text{P}_2\text{O}_7 \):** \[ \text{Molar mass of } \text{Mg}_2\text{P}_2\text{O}_7 = (2 \times 24) + (2 \times 31) + (7 \times 16) \] \[ = 48 + 62 + 112 = 222 \, \text{g/mol} \] ### Step 2: Calculate the mass of phosphorus in \( \text{Mg}_2\text{P}_2\text{O}_7 \) 1. **Determine the total mass of phosphorus in the compound:** \[ \text{Mass of P in } \text{Mg}_2\text{P}_2\text{O}_7 = 2 \times 31 = 62 \, \text{g} \] ### Step 3: Calculate the percentage of phosphorus in the organic compound 1. **Use the formula for percentage of phosphorus:** \[ \text{Percentage of P} = \left( \frac{\text{Mass of P in } \text{Mg}_2\text{P}_2\text{O}_7}{\text{Molar mass of } \text{Mg}_2\text{P}_2\text{O}_7} \times \text{Mass of } \text{Mg}_2\text{P}_2\text{O}_7 \right) \div \text{Mass of organic compound} \times 100 \] 2. **Substituting the values:** \[ \text{Percentage of P} = \left( \frac{62}{222} \times 0.1697 \right) \div 0.3160 \times 100 \] 3. **Calculating the values:** - Calculate the mass of phosphorus in the sample: \[ \text{Mass of P} = \frac{62}{222} \times 0.1697 \approx 0.0471 \, \text{g} \] - Now calculate the percentage: \[ \text{Percentage of P} = \left( \frac{0.0471}{0.3160} \right) \times 100 \approx 14.89\% \] ### Final Answer: The percentage of phosphorus in the organic compound is approximately **14.89%**. ---

To calculate the percentage of phosphorus in the organic compound, we will follow these steps: ### Step 1: Determine the molar mass of \( \text{Mg}_2\text{P}_2\text{O}_7 \) 1. **Calculate the molar mass of each element in the compound:** - Magnesium (Mg): \( 24 \, \text{g/mol} \) - Phosphorus (P): \( 31 \, \text{g/mol} \) - Oxygen (O): \( 16 \, \text{g/mol} \) ...
Promotional Banner

Similar Questions

Explore conceptually related problems

0.40 g of an organic compound containing phosphorus gave 0.444 g of Mg_2P_2O_7 by usual analysis. Calculate the percentage of phosphorus in the organic compound

1.5 g of an organic compound in a quantitative determination of phosphorus gave 2.5090 g of Mg_2 P_2 O_7 . Calculate the percentage of phosphorus in the compound.

0.12 gm of an organic compound containing phosphorus gave 0.22 gm of Mg_2P_2O_7 by the usual analysis. Calculate the percentage of phosphorus in the compound.

0.5 g of an organic substance containing phosphorus was heated with conc HNO_(3) in the carius tube, the phosphoric acid thus formed was precipitated with magnesia mixture (MgNH_(4)PO_(4)) which on ignition gave a residue to 1.0 g of megnesium pyrophosphate (Mg_(2)P_(2)O_(7)) The percentage of phosphorous in the organic compound is

0.092 g of an organic compound containing phosphorus gave 0.111 g Mg_(2)P_(2)O_(7) by usual analysis. Calculate the % of phosphorus in the organic compound.

0.5 gm of an organic substance containing prosphorous was heated with sonc. HNO_3 is the carius tube. The phosphoric acid thus formed was precipitated with magnesia mixture (MgNH_4PO_4) which on ignition gave a residue of 1.0 gm of magnesium phyrophosphate (Mg_2P_2O_7) . The precentage of phosphorous in the organic compound is:

0.40g of an organic compound containing phosphorus gave 0.555 g of Mg_(2)P_(2)O_(7) by usual analysis calculate the % of phosphorus in the organic compound

0.64 g of organic compound give 1.2535 g of Mg_(2)P_(2)O_(7) . percentage of P is

(i) In sulphur estimation , 0.157 g of organic compound gave 0.4813 g of BaSO_(4) . What is the percentage of sulphur in organic compound ? (ii) 0.092 g of organic compound heating is carius tube and susequent ignition gave 0.111 g of Mg_(2)P_(2)O_(7) . calculate the percentage of phosphorus in organic compound.

0.246 g of an organic substance when heated with excess of fuming nitric acid and silver nitrate gave 0.2584 g of silver bromide. Calculate the percentage of bromine in the compound.