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The IUPAC name of following compound is:...

The IUPAC name of following compound is:
`CH_(3)CH_(2) - underset(CH_(3))underset(|)overset(H)overset(|)(C) - underset(CH_(3))underset(|)overset(C_(4)H_(9))overset(|)(C) - CH_(3)`

A

3, 4, 4-Trimethylheptane

B

3, 4, 4-Trimethyloctane

C

2-Butyl-2-methyl-3-ethylbutane

D

2-Ethyl-3, 3-dimethylheptane

Text Solution

AI Generated Solution

The correct Answer is:
To determine the IUPAC name of the given compound, we will follow these steps: ### Step 1: Identify the Longest Carbon Chain - The first step in naming an organic compound is to identify the longest continuous carbon chain. In this case, the longest chain consists of 8 carbon atoms. ### Step 2: Number the Carbon Chain - Number the carbon chain starting from the end that gives the substituents the lowest possible numbers. In this case, if we number from the left, we get: 1. C1 2. C2 3. C3 4. C4 5. C5 6. C6 7. C7 8. C8 - This numbering gives us the lowest numbers for the substituents. ### Step 3: Identify and Name the Substituents - From the numbering, we can see that there are three methyl (–CH₃) groups attached to the carbon chain: - One methyl group at C3 - Two methyl groups at C4 - Therefore, we denote the substituents as "3,4,4-trimethyl". ### Step 4: Combine the Information - The parent chain has 8 carbons, which corresponds to the prefix "oct". - Since the compound is saturated (only single bonds), we use the suffix "ane". - Therefore, the full name of the compound is "3,4,4-trimethyl-octane". ### Final Answer The IUPAC name of the compound is **3,4,4-trimethyl-octane**. ---

To determine the IUPAC name of the given compound, we will follow these steps: ### Step 1: Identify the Longest Carbon Chain - The first step in naming an organic compound is to identify the longest continuous carbon chain. In this case, the longest chain consists of 8 carbon atoms. ### Step 2: Number the Carbon Chain - Number the carbon chain starting from the end that gives the substituents the lowest possible numbers. In this case, if we number from the left, we get: 1. C1 ...
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