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In Duma's method for estimation of nitro...

In Duma's method for estimation of nitrogen , `0.25` g of an organic compound gave 40 mL of nitrogen collected at 300 K temperature and 725 mm pressure . If the aqueous tension at 300 K is 25 mm , the percentage of nitrogen in the compound is

A

`16.76`

B

`15.76`

C

`17.36`

D

`18.20`

Text Solution

Verified by Experts

The correct Answer is:
A
Let us calculate volume of `N_(2)` evolved at N.T.P. Experimental conditions N.T.P. conditions
`{:(V_(1)=40 mL,V_(2)=?),(P_(1)=(725-25)=700mm,P_(2)=760 mm),(T_(1)=300 K,T_(2)=273 K):}`
By applying gas equation :
`(P_(1)V_(1))/T_(1)=(P_(2)V_(2))/T_(2)`
`V_(2)=(P_(1)V_(1)T_(2))/(P_(2)T_(1))`
`V_(2)=((700mm)xx(40 mL)xx(273 K))/((760mm)xx(300 K))`
`=33.52 mL`
`%` of `N=28/22400xx("Volume of "N_(2)" at N.T.P.")/("Mass of compound")xx100`
`=28/22400xx((33.52 mL))/((0.25 g))xx100`
`=16.76 %`
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