The unit cell edge length of NaF crystal is `4.634Å`. If the ionic radius of `Na^(+)` ion is 95 pm, what is the ionic radius of `F^(-)` ion, assuming that anion-anion contact and face centred cubic lattice?

Explanation

To find the ionic radius of the fluoride ion (F⁻) in the NaF crystal, we can follow these steps:

### Step-by-Step Solution:

1. **Convert the Edge Length from Angstroms to Picometers:**
The edge length of the NaF crystal is given as 4.634 Å. We know that:
\[
1 \text{ Å} = 100 \text{ pm}
...