Silver metal crystallises in a cubic closed- packed arrangement with the edge of the unit cell having a length, a = 407 pm. What is the radius of silver atom?

Explanation

To find the radius of a silver atom in a cubic close-packed (CCP) arrangement, we can follow these steps:

### Step 1: Understand the Structure
Silver crystallizes in a cubic close-packed (CCP) arrangement, which is also known as face-centered cubic (FCC). In this structure, atoms are located at each corner of the cube and at the centers of each face.

### Step 2: Use the Relationship Between Edge Length and Atomic Radius
In a face-centered cubic (FCC) structure, the relationship between the edge length (a) of the unit cell and the radius (R) of the atom is given by the formula:
\[ R = \frac{\sqrt{2}}{2} a \]
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